$AEF$ üçgeni ile $ADC$ üçgeni benzer. O zaman
$$\frac{\mid AE\mid }{\mid ED\mid}=\frac{\mid AF\mid}{\mid FC\mid}\ldots (1)$$
$ADF$ üçgeni ile $ABC$ üçgeni benzer. O zaman
$$\frac{\mid AD\mid}{\mid DB\mid }=\frac{\mid AF\mid }{\mid FC\mid}\ldots (2)$$
O halde $$(1),(2)\Rightarrow \frac{\mid AE\mid }{\mid ED\mid}=\frac{\mid AD\mid}{\mid DB\mid } \Rightarrow x=2 \,\ \text{cm}$$