Question

$x-5\sqrt {x}=3$

Olduguna gore

$x-\dfrac {15} {\sqrt {x}}$

Kactir?

Answer 1

$x-5\sqrt{x}=3 \\ x=3+5\sqrt{x}$

$x-\frac{15}{\sqrt{x}}=3+5\sqrt{x}-\frac{15}{\sqrt{x}}=\frac{3\sqrt{x}+5x-15}{\sqrt{x}}=\frac{3\sqrt{x}+5(x-3)}{\sqrt{x}}=\frac{3\sqrt{x}+25\sqrt{x}}{\sqrt{x}}=28$

Comments

Teşekkür ederim

Answer 2

$$\sqrt x(\sqrt x-5)=3$$

$$(\sqrt x-5)=\frac{3}{\sqrt x}$$

$$-5(\sqrt x-5)=\frac{-15}{\sqrt x}$$

$$x-5(\sqrt x-5)=x-\frac{15}{\sqrt x}$$

$$x-5\sqrt x+25)=x-\frac{15}{\sqrt x}$$

$$3+25=x-\frac{15}{\sqrt x}$$

$$28=x-\frac{15}{\sqrt x}$$