cot50.cos10 - [1/(4sin50)] = ?
Cevap kesirli bi sayı
$\frac{4.cot50.cos10.sin50-1}{4sin50}=\frac{4cos50.cos10-1}{4sin50}=\frac{4.\frac 12(cos60-cos40)-1}{4sin50}=\frac{2.\frac 12-2cos40-1}{4sin50}=\frac {-2cos40}{4sin50}=-\frac 12$