$sin3x=sin(2x-\frac{\pi}{6})$ denkleminin çözüm kümesi hangisidir?
A)$x:x=\frac{3\pi}{2}+k2\pi$ veya $x=\frac{\pi}{8}+k\frac{2\pi}{5},k\in Z$
B)$x:x=\frac{11\pi}{6}+k2\pi$ veya $x=\frac{\pi}{8}+k\frac{2\pi}{5},k\in Z$
C)$x:x=\frac{11\pi}{6}+k\pi$ veya $x=\frac{\pi}{30}+k\frac{11\pi}{2},k\in Z$
D)$x:x=\frac{11\pi}{6}+k2\pi$ veya $x=\frac{7\pi}{30}+k\frac{2\pi}{5},k\in Z$
E)$x:x=\frac{3\pi}{2}+k2\pi$ veya $x=\frac{\pi}{8}+k\frac{\pi}{2},k\in Z$