paralelkenar sorusu

Question

AD=5 AB=8 LK=√3 ise AL=?

Answer 1

$m(DLA)=m(LAB) \rightarrow |DL|=|DA|=5$

$|LC|=3$

$m(ABN)=m(LCN) \rightarrow [AK] \perp [KC]$

$[DH] \perp [AK]$ olsun.

$\triangle{DHK} \equiv \triangle{LKC}$

$\dfrac{|HL|}{|DL|}=\dfrac{|LK|}{|LC|}$

$\dfrac{\frac{x}{2}}{5}=\dfrac{\sqrt{3}}{3}$

$x=\dfrac{10 \sqrt{3}}{3}$