ABC ucgeninde [EF]\\[BC]
A(DEF)=2A(AFE) ise $\frac{|FE||}{BC|} kactir?
$A=\dfrac{h_1.x}{2}$$2A=\dfrac{h_2.x}{2}$ oranlarsak$\dfrac{1}{2}=\dfrac{h_1}{h_2}$$2.h_1=h_2$bize $\dfrac{h_1}{h_1+h_2}=\dfrac{|FE|}{|BC|}$ lazım$\dfrac{h_1}{3h_1}=\dfrac{|FE|}{|BC|}=1/3$
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