Önce Mehmet hocamın çözümüyle başlayalım...
$x=\sqrt[3]{\sqrt{337}+11}-\sqrt[3]{\sqrt{337}-11} \\ \Rightarrow x^3=\sqrt{337}+11-\sqrt{337}+11-3\sqrt[3]{\sqrt{337}+11}.\sqrt[3]{\sqrt{337}-11}(\underbrace{\sqrt[3]{\sqrt{337}+11}-\sqrt[3]{\sqrt{337}-11}}_x) \\ =22-3\sqrt[3]{337-121}.x=22-18x=x^3 \\ \Rightarrow x^3+18x=22$